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Periodic Table and Periodicity question

2022 · 27 Jun · Shift 1 · Q4
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Periodic Table and Periodicity question

2022 · 27 Jun · Shift 1 · Q4

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : The ionic radii of O2−O^{2-}O2− and Mg2+Mg^{2+}Mg2+ are same. Reason (R) : Both O2−O^{2-}O2− and Mg2+Mg^{2+}Mg2+ are isoelectronic species. In the light of the above statements, choose the correct answer from the options given below.
  1. A
    Both (A) and (R) are true and (R) is the correct explanation of (A).
  2. B
    Both (A) and (R) are true but (R) is not the correct explanation of (A).
  3. C
    (A) is true but (R) is false.
  4. D
    (A) is false but (R) is true.
View written solutionFree

Correct answer: D

  1. Check the Reason (R): Are O2−O^{2-}O2− and Mg2+Mg^{2+}Mg2+ isoelectronic?
  • Oxygen has atomic number 888.

  • In O2−O^{2-}O2−, it gains 222 electrons: 8+2=10 electrons8 + 2 = 10 \text{ electrons}8+2=10 electrons

  • Magnesium has atomic number 121212.

  • In Mg2+Mg^{2+}Mg2+, it loses 222 electrons: 12−2=10 electrons12 - 2 = 10 \text{ electrons}12−2=10 electrons

So, both ions have 101010 electrons.

Therefore, O2−O^{2-}O2− and Mg2+Mg^{2+}Mg2+ are isoelectronic species.

Hence, Reason (R) is true.


  1. Check the Assertion (A): Are the ionic radii of O2−O^{2-}O2− and Mg2+Mg^{2+}Mg2+ same?

Although they are isoelectronic, isoelectronic species do not necessarily have the same radius.

For an isoelectronic series, radius depends on nuclear charge:

  • Greater nuclear charge ⇒\Rightarrow⇒ stronger attraction on the same number of electrons
  • Hence, smaller radius

Now compare nuclear charges:

  • For O2−O^{2-}O2−: nuclear charge = 888
  • For Mg2+Mg^{2+}Mg2+: nuclear charge = 121212

Since Mg2+Mg^{2+}Mg2+ has much higher nuclear charge, it pulls the same 10 electrons more strongly. Thus, r(Mg2+)<r(O2−)r(Mg^{2+}) < r(O^{2-})r(Mg2+)<r(O2−)

So, their ionic radii are not same.

Hence, Assertion (A) is false.


  1. Evaluate the options
  • A: Both true, and R explains A →\rightarrow→ False
  • B: Both true, but R not explanation →\rightarrow→ False
  • C: A true, R false →\rightarrow→ False
  • D: A false, R true →\rightarrow→ Correct

  1. Final Answer

The correct option is: D\boxed{D}D​


  1. Comparison with stored correct answer

Stored correct answer: DDD

My derived answer also is DDD, so they agree.

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