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Periodic Table and Periodicity question

2022 · 28 Jun · Shift 2 · Q5
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  5. /2022 · 28 Jun · Shift 2 · Q5

Periodic Table and Periodicity question

2022 · 28 Jun · Shift 2 · Q5

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1

Match List - I with List - II :

List-I (Oxide) List-II (Nature)
(A) Cl2O7C{l_2}{O_7}Cl2​O7​ (I) Amphoteric
(B) Na2ON{a_2}ONa2​O (II) Basic
(C) Al2O3A{l_2}{O_3}Al2​O3​ (III) Neutral
(D) N2O{N_2}ON2​O (IV) Acidic

Choose the correct answer from the options given below :

  1. A
    (A) - (IV), (B) - (III), (C) - (I), (D) - (II)
  2. B
    (A) - (IV), (B) - (II), (C) - (I), (D) - (III)
  3. C
    (A) - (II), (B) - (IV), (C) - (III), (D) - (I)
  4. D
    (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
View written solutionFree

Correct answer: B

  1. Identify the nature of each oxide

    We match each oxide in List-I with its nature in List-II.

    (A) Cl2O7Cl_2O_7Cl2​O7​

    Cl2O7Cl_2O_7Cl2​O7​ is the anhydride of perchloric acid: Cl2O7+H2O→2HClO4Cl_2O_7 + H_2O \rightarrow 2HClO_4Cl2​O7​+H2​O→2HClO4​ Since it forms an acid with water, it is an acidic oxide.

    So, (A)→(IV)(A) \to (IV)(A)→(IV)

    (B) Na2ONa_2ONa2​O

    Na2ONa_2ONa2​O is an oxide of an alkali metal. Alkali metal oxides are strongly basic. It reacts with water as: Na2O+H2O→2NaOHNa_2O + H_2O \rightarrow 2NaOHNa2​O+H2​O→2NaOH So, (B)→(II)(B) \to (II)(B)→(II)

    (C) Al2O3Al_2O_3Al2​O3​

    Al2O3Al_2O_3Al2​O3​ reacts with both acids and bases, so it is amphoteric.

    So, (C)→(I)(C) \to (I)(C)→(I)

    (D) N2ON_2ON2​O

    N2ON_2ON2​O is a neutral oxide. It is neither acidic nor basic.

    So, (D)→(III)(D) \to (III)(D)→(III)

  2. Final matching

    (A)−(IV),(B)−(II),(C)−(I),(D)−(III)(A)-(IV),\quad (B)-(II),\quad (C)-(I),\quad (D)-(III)(A)−(IV),(B)−(II),(C)−(I),(D)−(III)

  3. Compare with options

    This corresponds to Option B.

  4. Comparison with stored answer

    Stored correct answer = B

    Our derived answer = B

    Hence, they agree.

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