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Periodic Table and Periodicity question

2011 · Shift 0 · Q27
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Periodic Table and Periodicity question

2011 · Shift 0 · Q27

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1
Which one of the following order represents the correct sequence of the increasing basic nature of the given oxides ?
  1. A
    MgOMgOMgO < K2OK_2OK2​O < Al2O3Al_2O_3Al2​O3​ < Na2ONa_2ONa2​O
  2. B
    Al2O3Al_2O_3Al2​O3​ < MgOMgOMgO < Na2ONa_2ONa2​O < K2OK_2OK2​O
  3. C
    Na2ONa_2ONa2​O < K2OK_2OK2​O < MgOMgOMgO < Al2O3Al_2O_3Al2​O3​
  4. D
    K2OK_2OK2​O < Na2ONa_2ONa2​O < Al2O3Al_2O_3Al2​O3​ < MgOMgOMgO
View written solutionFree

Correct answer: B

  1. Basic nature of oxides across a period

    Metallic oxides are generally basic, while amphoteric oxides show weaker basic character.

    • Alkali metal oxides like Na2ONa_2ONa2​O and K2OK_2OK2​O are strongly basic.
    • Alkaline earth metal oxide like MgOMgOMgO is basic, but less basic than alkali metal oxides.
    • Al2O3Al_2O_3Al2​O3​ is amphoteric, so it is the least basic among these.
  2. Compare the given oxides

    • Al2O3Al_2O_3Al2​O3​ : amphoteric, hence least basic
    • MgOMgOMgO : basic
    • Na2ONa_2ONa2​O : strongly basic
    • K2OK_2OK2​O : more basic than Na2ONa_2ONa2​O
  3. Why is K2OK_2OK2​O more basic than Na2ONa_2ONa2​O?

    Down Group 1, metallic character increases, so the oxides become more ionic and more strongly basic.

    Hence: K2O>Na2OK_2O > Na_2OK2​O>Na2​O

  4. Overall increasing order of basic nature

    Therefore, the correct increasing order is Al2O3<MgO<Na2O<K2OAl_2O_3 < MgO < Na_2O < K_2OAl2​O3​<MgO<Na2​O<K2​O

  5. Match with options

    This corresponds to Option B.

  6. Verification with stored answer

    Stored correct answer: B

    Derived answer: B

    So, the derived answer agrees with the stored answer.

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