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Periodic Table and Periodicity question

2011 · Shift 0 · Q10
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Periodic Table and Periodicity question

2011 · Shift 0 · Q10

JEE MainChemistryPeriodic Table and PeriodicityMCQ+4 / −1
Outer electronic configuration of Gd (Atomic no : 64) is -
  1. A
    4f85d06s2
  2. B
    4f45d46s2
  3. C
    4f75d16s2
  4. D
    4f35d56s2
View written solutionFree

Correct answer: C

  1. Write the expected electronic filling for Gadolinium, Z=64Z=64Z=64

    Gadolinium comes after Xenon, so its inner core is: [Xe][Xe][Xe]

    After [Xe][Xe][Xe], electrons enter the 6s6s6s, 4f4f4f, and sometimes 5d5d5d subshells.

  2. Recall the lanthanide pattern

    In the lanthanide series, the general filling is close to: [Xe]4fn5d0 or 16s2[Xe]4f^n 5d^{0\text{ or }1} 6s^2[Xe]4fn5d0 or 16s2

    Gadolinium is a special case because it achieves extra stability with a half-filled 4f4f4f subshell.

  3. Find the stable configuration of Gd

    For Gd (Z=64Z=64Z=64), the configuration is: [Xe]4f75d16s2[Xe]4f^7 5d^1 6s^2[Xe]4f75d16s2

    Check total electrons beyond xenon: 7+1+2=107+1+2=107+1+2=10 Since Xenon has 545454 electrons, 54+10=6454+10=6454+10=64 which matches Gd.

  4. Compare with the options

    • A: 4f85d06s24f^8 5d^0 6s^24f85d06s2
      Not the accepted ground-state configuration for Gd.

    • B: 4f45d46s24f^4 5d^4 6s^24f45d46s2
      Incorrect.

    • C: 4f75d16s24f^7 5d^1 6s^24f75d16s2
      Correct.

    • D: 4f35d56s24f^3 5d^5 6s^24f35d56s2
      Incorrect.

  5. Final answer

    The outer electronic configuration of Gd is: 4f75d16s2\boxed{4f^7 5d^1 6s^2}4f75d16s2​

    So, the correct option is C.

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