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Electrochemistry question

2024 · 9 Apr · Shift 2 · Q9
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  5. /2024 · 9 Apr · Shift 2 · Q9

Electrochemistry question

2024 · 9 Apr · Shift 2 · Q9

JEE MainChemistryElectrochemistryMCQ+4 / −1

Match List I with List II

LIST I
(Cell)
LIST II
(Use/Property/Reaction)
A. Leclanche cell I. Converts energy of combustion into electrical energy
B. Ni - Cd cell II. Does not involve any ion in solution and is used in hearing aids
C. Fuel cell III. Rechargeable
D. Mercury cell IV. Reaction at anode Zn→Zn2++2e−\mathrm{Zn} \rightarrow \mathrm{Zn}^{2+}+2 \mathrm{e}^{-}Zn→Zn2++2e−

Choose the correct answer from the options given below :

  1. A
    A-III, B-I, C-IV, D-II
  2. B
    A-I, B-II, C-III, D-IV
  3. C
    A-IV, B-III, C-I, D-II
  4. D
    A-II, B-III, C-IV, D-I
View written solutionFree

Correct answer: C

  1. Identify each cell from List I and recall its key property/use/reaction.

  1. Leclanche cell

A Leclanche cell is the common dry cell.

  • The anode is zinc container.
  • Oxidation at anode is: Zn→Zn2++2e−\mathrm{Zn} \rightarrow \mathrm{Zn}^{2+} + 2e^-Zn→Zn2++2e−

So, A→IVA \to IVA→IV


  1. Ni-Cd cell

Nickel-cadmium cell is a secondary cell, i.e. it is rechargeable.

So, B→IIIB \to IIIB→III


  1. Fuel cell

A fuel cell converts the chemical energy of combustion directly into electrical energy.

So, C→IC \to IC→I


  1. Mercury cell

Mercury cell:

  • is used in small devices like hearing aids,
  • has paste electrolyte and no free aqueous ion participation in the usual sense of solution chemistry.

So, D→IID \to IID→II


  1. Final matching

Thus the correct match is:

  • A−IVA- IVA−IV
  • B−IIIB- IIIB−III
  • C−IC- IC−I
  • D−IID- IID−II

This corresponds to Option C.


  1. Comparison with stored correct answer

Stored correct answer = C

Our derived answer = C

Hence, they agree.

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