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Electrochemistry question

2022 · 28 Jun · Shift 2 · Q15

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JEE Main
Chemistry
Electrochemistry
2022 · 28 Jun · Shift 2 · Q15

Electrochemistry question

2022 · 28 Jun · Shift 2 · Q15

JEE MainChemistryElectrochemistryNumerical+4 / −1

For the given reactions

Sn^{2+}

+ 2e

-\to

Sn

Sn^{4+}

+ 4e

-\to

Sn the electrode potentials are ;

E_{S{n^{2 + }}/Sn}^o = - 0.140

V and

E_{S{n^{4 + }}/Sn}^o = + 0.010

V. The magnitude of standard electrode potential for

S{n^{4 + }}/S{n^{2 + }}

i.e.

E_{S{n^{4 + }}/S{n^{2 + }}}^o

is

\underline{\hspace{2cm}}

\times

10

-

2 V. (Nearest integer)

Numerical answer

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