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Electrochemistry question

2019 · 12 Apr · Shift 1 · Q3

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JEE Main
Chemistry
Electrochemistry
2019 · 12 Apr · Shift 1 · Q3

Electrochemistry question

2019 · 12 Apr · Shift 1 · Q3

JEE MainChemistryElectrochemistryMCQ+4 / −1

Given

CO_3^+

+ e–

\to

CO^{2+}

; Eo = + 1.81 V

Pb^{4+}

+ 2e–

\to

Pb^{2+}

; Eo = + 1.67 V

Ce^{4+}

+ e–

\to

Ce^{3+}

; Eo = + 1.61 V

Bi^{3+}

+ 3e–

\to

Bi

; Eo = + 0.20 V Oxidizing power of the species will increase in the order :

A
$Co^{3+}$ < $Ce^{4+}$ < $Bi^{3+}$ < $Pb^{4+}$
B
$Co^{3+}$ < $Pb^{4+}$ < $Ce^{4+}$ < $Bi^{3+}$
C
$Ce^{4+}$ < $Pb^{4+}$ < $Bi^{3+}$ < $Co^{3+}$
D
$Bi^{3+}$ < $Ce^{4+}$ < $Pb^{4+}$ < $Co^{3+}$

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