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Electrochemistry question

2019 · 11 Jan · Shift 2 · Q11

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JEE Main
Chemistry
Electrochemistry
2019 · 11 Jan · Shift 2 · Q11

Electrochemistry question

2019 · 11 Jan · Shift 2 · Q11

JEE MainChemistryElectrochemistryMCQ+4 / −1

Given the equilibrium constant: KC of the reaction :

Cu

(s) + 2

Ag^+

(aq)

\to

Cu^{2+}

(aq) + 2

Ag

(s) is 10

\times

1015, calculate the E

_{cell}^0

of this reaciton at 298 K [2.303

{{RT} \over F}

at 298 K = 0.059V]

A
0.4736 mV
B
0.04736 V
C
0.4736 V
D
0.04736 mV

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