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D and F Block Elements question

2023 · 24 Jan · Shift 1 · Q5
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  5. /2023 · 24 Jan · Shift 1 · Q5

D and F Block Elements question

2023 · 24 Jan · Shift 1 · Q5

JEE MainChemistryD and F Block ElementsMCQ+4 / −1
An ammoniacal metal salt solution gives a brilliant red precipitate on addition of dimethylglyoxime. The metal ion is :
  1. A
    Co 2+^{2+}2+
  2. B
    Fe 2+^{2+}2+
  3. C
    Ni 2+^{2+}2+
  4. D
    Cu 2+^{2+}2+
View written solutionFree

Correct answer: C

  1. Identify the reagent and the characteristic test

    Dimethylglyoxime (DMG) is a very important analytical reagent used for detecting certain metal ions.

    In an ammoniacal medium, DMG gives a brilliant red precipitate specifically with nickel(II) ions.

  2. Recall the reaction

    Nickel(II) reacts with dimethylglyoxime in ammoniacal solution to form a red chelate complex:

    Ni2++2 DMG→Ni(DMG)2↓\text{Ni}^{2+} + 2\,\text{DMG} \rightarrow \text{Ni(DMG)}_2 \downarrowNi2++2DMG→Ni(DMG)2​↓

    This precipitate is characteristically bright/brilliant red.

  3. Check the options

    • A: Co2+\text{Co}^{2+}Co2+ — does not give the characteristic brilliant red DMG precipitate.
    • B: Fe2+\text{Fe}^{2+}Fe2+ — does not give this test.
    • C: Ni2+\text{Ni}^{2+}Ni2+ — yes, gives a brilliant red precipitate of nickel dimethylglyoximate.
    • D: Cu2+\text{Cu}^{2+}Cu2+ — does not give this characteristic red precipitate.
  4. Conclusion

    Therefore, the metal ion is:

    Ni2+\boxed{\text{Ni}^{2+}}Ni2+​

    So the correct option is C.

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