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Coordination Compounds question

2019 · 9 Jan · Shift 2 · Q12
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Coordination Compounds question

2019 · 9 Jan · Shift 2 · Q12

JEE MainChemistryCoordination CompoundsMCQ+4 / −1
Homoleptic octahedral complexes of a metal ion 'M3+M^{3+}M3+' with three monodenate ligands L1L_1L1​, L2L_2L2​ and L3L_3L3​ adsorb wavelenths in the region of green, blue and red respectively. The increasing order of the ligands strength is :
  1. A
    L3L_3L3​ < L1L_1L1​ < L2L_2L2​
  2. B
    L3L_3L3​ < L2L_2L2​ < L1L_1L1​
  3. C
    L1 < L2 < L3
  4. D
    L2 < L1 < L3
View written solutionFree

Correct answer: A

  1. For homoleptic octahedral complexes, the color absorbed corresponds to the crystal field splitting energy Δo\Delta_oΔo​:

Δo=hν=hcλ\Delta_o = h\nu = \frac{hc}{\lambda}Δo​=hν=λhc​

So, larger Δo\Delta_oΔo​ means smaller absorbed wavelength λ\lambdaλ.

  1. The ligand strength is directly related to the magnitude of Δo\Delta_oΔo​:
  • stronger ligand ⇒\Rightarrow⇒ larger Δo\Delta_oΔo​
  • weaker ligand ⇒\Rightarrow⇒ smaller Δo\Delta_oΔo​
  1. Given absorbed wavelengths:
  • L1L_1L1​ absorbs green
  • L2L_2L2​ absorbs blue
  • L3L_3L3​ absorbs red

In the visible region, wavelength order is:

λred>λgreen>λblue\lambda_{\text{red}} > \lambda_{\text{green}} > \lambda_{\text{blue}}λred​>λgreen​>λblue​

Therefore, energy order is opposite:

Ered<Egreen<EblueE_{\text{red}} < E_{\text{green}} < E_{\text{blue}}Ered​<Egreen​<Eblue​

Hence,

Δo(L3)<Δo(L1)<Δo(L2)\Delta_o(L_3) < \Delta_o(L_1) < \Delta_o(L_2)Δo​(L3​)<Δo​(L1​)<Δo​(L2​)

  1. Since ligand strength increases with Δo\Delta_oΔo​, the increasing order of ligand strength is:

L3<L1<L2L_3 < L_1 < L_2L3​<L1​<L2​

  1. Checking options:
  • A: L3<L1<L2L_3 < L_1 < L_2L3​<L1​<L2​ ✔
  • B: L3<L2<L1L_3 < L_2 < L_1L3​<L2​<L1​ ✘
  • C: L1<L2<L3L_1 < L_2 < L_3L1​<L2​<L3​ ✘
  • D: L2<L1<L3L_2 < L_1 < L_3L2​<L1​<L3​ ✘

Therefore, the correct option is A.

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