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Compounds Containing Nitrogen question

2023 · 6 Apr · Shift 1 · Q11
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  5. /2023 · 6 Apr · Shift 1 · Q11

Compounds Containing Nitrogen question

2023 · 6 Apr · Shift 1 · Q11

JEE MainChemistryCompounds Containing NitrogenMCQ+4 / −1
JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 54 English Compound P\mathrm{P}P is neutral, Q\mathrm{Q}Q gives effervescence with NaHCO3\mathrm{NaHCO}_{3}NaHCO3​ while R\mathrm{R}R reacts with Hinsbergs reagent to give solid soluble in NaOH\mathrm{NaOH}NaOH. Compound P\mathrm{P}P is
  1. A
    JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 54 English Option 1
  2. B
    JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 54 English Option 2
  3. C
    JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 54 English Option 3
  4. D
    JEE Main 2023 (Online) 6th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 54 English Option 4
View written solutionFree

Correct answer: B

  1. We are told about three compounds formed in sequence/related by functionality tests:
  • PPP is neutral.
  • QQQ gives effervescence with NaHCO3\mathrm{NaHCO_3}NaHCO3​.
  • RRR reacts with Hinsberg's reagent to give a solid soluble in NaOH\mathrm{NaOH}NaOH.

We identify each from the qualitative tests.


  1. Interpret the test for RRR:

Hinsberg reagent is benzenesulphonyl chloride.

  • Primary amine gives sulphonamide containing an acidic N−HN-HN−H, so the product is soluble in NaOH.
  • Secondary amine gives sulphonamide insoluble in NaOH.
  • Tertiary amine does not form such sulphonamide.

Therefore, RRR must be a primary amine.


  1. Interpret the test for QQQ:

Effervescence with NaHCO3\mathrm{NaHCO_3}NaHCO3​ indicates evolution of CO2\mathrm{CO_2}CO2​, so QQQ must be a carboxylic acid.

RCOOH+NaHCO3→RCOONa+CO2↑+H2O\mathrm{RCOOH + NaHCO_3 \rightarrow RCOONa + CO_2 \uparrow + H_2O}RCOOH+NaHCO3​→RCOONa+CO2​↑+H2​O

Thus, QQQ is a carboxylic acid.


  1. Now relate PPP, QQQ, and RRR.

A very standard organic conversion is:

  • Nitrile on hydrolysis gives carboxylic acid.
  • Nitrile on reduction gives primary amine.

That is,

R−C≡N→hydrolysisR−COOH\mathrm{R-C\equiv N \xrightarrow[hydrolysis]{} R-COOH}R−C≡Nhydrolysis​R−COOH

and

R−C≡N→reductionR−CH2NH2\mathrm{R-C\equiv N \xrightarrow[reduction]{} R-CH_2NH_2}R−C≡Nreduction​R−CH2​NH2​

A nitrile is generally neutral, matching the property of PPP.

So:

  • P=P =P= nitrile
  • Q=Q =Q= carboxylic acid
  • R=R =R= primary amine

  1. Therefore, among the options, PPP must be the nitrile compound.

Since the stored correct answer is B, option B must correspond to the nitrile structure.

Hence, the correct answer is B.

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