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Compounds Containing Nitrogen question

2023 · 10 Apr · Shift 1 · Q10
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Compounds Containing Nitrogen question

2023 · 10 Apr · Shift 1 · Q10

JEE MainChemistryCompounds Containing NitrogenMCQ+4 / −1
Isomeric amines with molecular formula C 8_88​ H 11_{11}11​ N give the following tests Isomer (P) ⇒\Rightarrow⇒ Can be prepared by Gabriel phthalimide synthesis Isomer (Q) ⇒\Rightarrow⇒ Reacts with Hinsberg's reagent to give solid insoluble in NaOH Isomer (R) ⇒\Rightarrow⇒ Reacts with HONO followed by β\betaβ-naphthol in NaOH to give red dye. Isomers (P), (Q) and (R) respectively are
  1. A
    JEE Main 2023 (Online) 10th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 57 English Option 1
  2. B
    JEE Main 2023 (Online) 10th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 57 English Option 2
  3. C
    JEE Main 2023 (Online) 10th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 57 English Option 3
  4. D
    JEE Main 2023 (Online) 10th April Morning Shift Chemistry - Compounds Containing Nitrogen Question 57 English Option 4
View written solutionFree

Correct answer: C

  1. Interpret each test

    We are given three isomeric amines with molecular formula C8H11N\mathrm{C_8H_{11}N}C8​H11​N.

    We must identify:

    • PPP: can be prepared by Gabriel phthalimide synthesis
    • QQQ: with Hinsberg reagent gives a solid insoluble in NaOH
    • RRR: with HONO\mathrm{HONO}HONO followed by β\betaβ-naphthol in NaOH gives red dye
  2. Meaning of each test

    (i) Gabriel phthalimide synthesis

    Gabriel synthesis prepares only primary alkyl amines effectively, not aryl amines, not secondary/tertiary amines.

    So PPP must be a primary amine.

    (ii) Hinsberg test

    • Primary amine: forms sulphonamide containing N–H, soluble in NaOH.
    • Secondary amine: forms sulphonamide without N–H, hence insoluble in NaOH.
    • Tertiary amine: generally does not form sulphonamide.

    Therefore QQQ must be a secondary amine.

    (iii) Reaction with HONO\mathrm{HONO}HONO, then coupling with β\betaβ-naphthol

    This is the diazotization + azo coupling test, given by primary aromatic amines.

    Therefore RRR must be a primary aromatic amine.

  3. Find isomeric amines of formula C8H11N\mathrm{C_8H_{11}N}C8​H11​N

    Let us list common isomers fitting this formula:

    • Primary aliphatic amine: C6H5CH2CH2NH2\mathrm{C_6H_5CH_2CH_2NH_2}C6​H5​CH2​CH2​NH2​ (phenethylamine)
    • Primary aromatic amine: C6H4(CH3)(NH2)\mathrm{C_6H_4(CH_3)(NH_2)}C6​H4​(CH3​)(NH2​) i.e. toluidines (ooo-, mmm-, ppp-toluidine)
    • Secondary amine: C6H5NHCH3\mathrm{C_6H_5NHCH_3}C6​H5​NHCH3​ (N-methylaniline)
    • Another secondary amine: C6H5CH2NHCH3\mathrm{C_6H_5CH_2NHCH_3}C6​H5​CH2​NHCH3​ would be C8H11N\mathrm{C_8H_{11}N}C8​H11​N? Check: benzyl methyl amine = C8H11N\mathrm{C_8H_{11}N}C8​H11​N yes, but it is not aromatic primary.
  4. Assign identities using tests

    For RRR

    Since it gives diazotization followed by azo dye formation, it must be a primary aromatic amine.

    Hence RRR is toluidine (ooo/mmm/ppp-toluidine).

    For QQQ

    It gives Hinsberg product insoluble in NaOH, so it must be a secondary amine.

    The suitable aromatic secondary amine is N-methylaniline.

    For PPP

    It can be prepared by Gabriel synthesis, so it should be a primary aliphatic amine.

    Hence PPP is phenethylamine C6H5CH2CH2NH2\mathrm{C_6H_5CH_2CH_2NH_2}C6​H5​CH2​CH2​NH2​.

  5. Final identification

    Therefore,

    P=C6H5CH2CH2NH2(primary aliphatic amine)P = \mathrm{C_6H_5CH_2CH_2NH_2} \quad (\text{primary aliphatic amine})P=C6​H5​CH2​CH2​NH2​(primary aliphatic amine) Q=C6H5NHCH3(secondary amine, N-methylaniline)Q = \mathrm{C_6H_5NHCH_3} \quad (\text{secondary amine, N-methylaniline})Q=C6​H5​NHCH3​(secondary amine, N-methylaniline) R=CH3C6H4NH2(toluidine, primary aromatic amine)R = \mathrm{CH_3C_6H_4NH_2} \quad (\text{toluidine, primary aromatic amine})R=CH3​C6​H4​NH2​(toluidine, primary aromatic amine)

  6. Match with options

    This corresponds to Option C.

  7. Comparison with stored answer

    Stored correct answer: C

    Our derived answer: C

    So they agree.

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