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Chemical Kinetics and Nuclear Chemistry question

2020 · 6 Sep · Shift 2 · Q7
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Chemical Kinetics and Nuclear Chemistry question

2020 · 6 Sep · Shift 2 · Q7

JEE MainChemistryChemical Kinetics and Nuclear ChemistryNumerical+4 / −1
The rate of a reaction decreased by 3.555 times when the temperature was changed from 40oC to 30oC. The activation energy (in kJ mol–1) of the reaction is ‾\underline{\hspace{2cm}}​. Take; R = 8.314 J mol–1 K–1 ln 3.555 = 1.268
Numerical answer
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