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Chemical Kinetics and Nuclear Chemistry question

2019 · 9 Apr · Shift 1 · Q9
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Chemical Kinetics and Nuclear Chemistry question

2019 · 9 Apr · Shift 1 · Q9

JEE MainChemistryChemical Kinetics and Nuclear ChemistryMCQ+4 / −1
The given plots represent the variation of the concentration of a reactant R with time for two different reactions (i) and (ii). The respective orders of the reactions are : JEE Main 2019 (Online) 9th April Morning Slot Chemistry - Chemical Kinetics and Nuclear Chemistry Question 140 English
  1. A
    0,1
  2. B
    1,0
  3. C
    0,2
  4. D
    1,1
View written solutionFree

Correct answer: B

  1. Use the characteristic concentration–time plots for different orders

For a reactant RRR, the integrated rate laws give these standard shapes:

  • Zero-order reaction: [R]=[R]0−kt[R] = [R]_0 - kt[R]=[R]0​−kt So, a plot of [R][R][R] vs ttt is a straight line with negative slope.

  • First-order reaction: [R]=[R]0e−kt[R] = [R]_0 e^{-kt}[R]=[R]0​e−kt So, a plot of [R][R][R] vs ttt is a curved exponential decay.

  1. Interpret the two given plots

From the figure:

  • Reaction (i) shows a curved decrease of concentration with time. Hence, reaction (i) is first order.

  • Reaction (ii) shows a straight-line decrease of concentration with time. Hence, reaction (ii) is zero order.

  1. Match with the options

Thus, the respective orders for reactions (i)(i)(i) and (ii)(ii)(ii) are: 1,01,01,0

This corresponds to Option B.

  1. Comparison with stored correct answer

Stored correct answer = B.

Our derived answer = B.

So, the answer agrees with the stored correct answer.

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