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Chemical Kinetics and Nuclear Chemistry question

2002 · Shift 0 · Q37
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Chemical Kinetics and Nuclear Chemistry question

2002 · Shift 0 · Q37

JEE MainChemistryChemical Kinetics and Nuclear ChemistryMCQ+4 / −1
Units of rate constant of first and zero order reactions in terms of molarity M unit are respectively
  1. A
    sec-1, Msec-1
  2. B
    sec-1, M
  3. C
    Msec-1, sec-1
  4. D
    M, sec-1
View written solutionFree

Correct answer: A

  1. Write the rate law and use units of rate

    Rate of reaction always has units of concentration per unit time: Rate=molaritytime=M s−1\text{Rate} = \frac{\text{molarity}}{\text{time}} = M\,s^{-1}Rate=timemolarity​=Ms−1

  2. First-order reaction

    For a first-order reaction: Rate=k[A]\text{Rate} = k[A]Rate=k[A]

    Therefore, k=Rate[A]=M s−1M=s−1k = \frac{\text{Rate}}{[A]} = \frac{M\,s^{-1}}{M} = s^{-1}k=[A]Rate​=MMs−1​=s−1

    So, the unit of rate constant for a first-order reaction is: s−1orsec−1s^{-1} \quad \text{or} \quad \text{sec}^{-1}s−1orsec−1

  3. Zero-order reaction

    For a zero-order reaction: Rate=k[A]0=k\text{Rate} = k[A]^0 = kRate=k[A]0=k

    Hence, the unit of kkk is same as the unit of rate: k=M s−1k = M\,s^{-1}k=Ms−1

    So, the unit of rate constant for a zero-order reaction is: M sec−1M\,\text{sec}^{-1}Msec−1

  4. Match with options

    Required order: first-order, zero-order

    • First-order: sec−1\text{sec}^{-1}sec−1
    • Zero-order: M sec−1M\,\text{sec}^{-1}Msec−1

    This matches Option A.

  5. Comparison with stored answer

    Stored correct answer: A

    My derived answer: A

    So, they agree.

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