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Chemical Kinetics and Nuclear Chemistry question

2002 · Shift 0 · Q41
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Chemical Kinetics and Nuclear Chemistry question

2002 · Shift 0 · Q41

JEE MainChemistryChemical Kinetics and Nuclear ChemistryMCQ+4 / −1
β\betaβ - particle is emitted in radioactivity by
  1. A
    conversion of proton to neutron
  2. B
    from outermost orbit
  3. C
    conversion of neutron to proton
  4. D
    β\betaβ -particle is not emitted
View written solutionFree

Correct answer: C

  1. Understand what a β\betaβ-particle is

    In nuclear radioactivity, a β\betaβ-particle usually means a β−\beta^-β− particle, which is an electron emitted from the nucleus.

  2. Process responsible for β−\beta^-β− emission

    In β−\beta^-β− decay, a neutron converts into a proton inside the nucleus:

    n→p+e−+νˉn \rightarrow p + e^- + \bar{\nu}n→p+e−+νˉ

    Here:

    • nnn = neutron
    • ppp = proton
    • e−e^-e− = β\betaβ-particle
    • νˉ\bar{\nu}νˉ = antineutrino
  3. Check each option

    • A: conversion of proton to neutron
      This corresponds to β+\beta^+β+ decay / positron-related process, not ordinary β−\beta^-β− emission. So this is incorrect.

    • B: from outermost orbit
      A β\betaβ-particle is not emitted from electronic orbit, but from the nucleus. So this is incorrect.

    • C: conversion of neutron to proton
      This is exactly the process of β−\beta^-β− decay. So this is correct.

    • D: β\betaβ-particle is not emitted
      This is clearly incorrect.

  4. Final answer

    The correct option is:

    C\boxed{\text{C}}C​

  5. Comparison with stored correct answer

    Stored correct answer = C
    Derived answer = C
    Hence, they agree.

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