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Chemical Equilibrium question

2025 · 23 Jan · Shift 2 · Q15
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  5. /2025 · 23 Jan · Shift 2 · Q15

Chemical Equilibrium question

2025 · 23 Jan · Shift 2 · Q15

JEE MainChemistryChemical EquilibriumMCQ+4 / −1
Consider the reaction X2Y( g)⇌X2( g)+12Y2( g)\mathrm{X}_2 \mathrm{Y}(\mathrm{~g}) \rightleftharpoons \mathrm{X}_2(\mathrm{~g})+\frac{1}{2} \mathrm{Y}_2(\mathrm{~g})X2​Y( g)⇌X2​( g)+21​Y2​( g) The equation representing correct relationship between the degree of dissociation (x) of X2Y(g)\mathrm{X}_2 \mathrm{Y}(\mathrm{g})X2​Y(g) with its equilibrium constant Kp is ‾\underline{\hspace{2cm}}​. Assume xxx to be very very small.
  1. A
    x=Kpp3x=\sqrt[3]{\frac{\mathrm{Kp}}{\mathrm{p}}}x=3pKp​​
  2. B
    x=Kp2p3x=\sqrt[3]{\frac{\mathrm{Kp}}{2 \mathrm{p}}}x=32pKp​​
  3. C
    x=2Kp2p3x=\sqrt[3]{\frac{2 \mathrm{Kp}^2}{\mathrm{p}}}x=3p2Kp2​​
  4. D
    x=2Kpp3x=\sqrt[3]{\frac{2 \mathrm{Kp}}{\mathrm{p}}}x=3p2Kp​​
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