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Chemical Equilibrium question

2021 · 26 Aug · Shift 2 · Q21
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  5. /2021 · 26 Aug · Shift 2 · Q21

Chemical Equilibrium question

2021 · 26 Aug · Shift 2 · Q21

JEE MainChemistryChemical EquilibriumNumerical+4 / −1
The reaction rate for the reaction [PtCl4]2−[PtCl_4]^{2-}[PtCl4​]2−+ H2OH_2OH2​O ⇌\rightleftharpoons⇌[Pt(H2O)Cl3]−[Pt(H_2O)Cl_3]^-[Pt(H2​O)Cl3​]− + Cl−Cl^-Cl− was measured as a function of concentrations of different species. It was observed that −d[[PtCl4]2−]dt=4.8×10−5[[PtCl4]2−]−2.4×10−3[[Pt(H2O)Cl3]−][Cl−]{{ - d\left[ {{{\left[ {PtC{l_4}} \right]}^{2 - }}} \right]} \over {dt}} = 4.8 \times {10^{ - 5}}\left[ {{{\left[ {PtC{l_4}} \right]}^{2 - }}} \right] - 2.4 \times {10^{ - 3}}\left[ {{{\left[ {Pt({H_2}O)C{l_3}} \right]}^ - }} \right]\left[ {C{l^ - }} \right]dt−d[[PtCl4​]2−]​=4.8×10−5[[PtCl4​]2−]−2.4×10−3[[Pt(H2​O)Cl3​]−][Cl−]. where square brackets are used to denote molar concentrations. The equilibrium constant Kc = ‾\underline{\hspace{2cm}}​ . (Nearest integer)
Numerical answer
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