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Chemical Equilibrium question

2020 · 9 Jan · Shift 2 · Q18
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Chemical Equilibrium question

2020 · 9 Jan · Shift 2 · Q18

JEE MainChemistryChemical EquilibriumMCQ+4 / −1
In the figure shown below reactant A (represented by square) is in equilibrium with product B (represented by circle). The equilibrium constant is : JEE Main 2020 (Online) 9th January Evening Slot Chemistry - Chemical Equilibrium Question 73 English
  1. A
    1
  2. B
    2
  3. C
    8
  4. D
    4
View written solutionFree

Correct answer: B

  1. Let the equilibrium be written as:

A⇌BA \rightleftharpoons BA⇌B

Since no coefficients are given, the equilibrium constant is

K=[B][A]K = \frac{[B]}{[A]}K=[A][B]​

  1. From the figure, count the particles at equilibrium:
  • Squares represent AAA
  • Circles represent BBB

From the diagram:

  • Number of AAA particles =4= 4=4
  • Number of BBB particles =8= 8=8
  1. Therefore,

K=[B][A]=84=2K = \frac{[B]}{[A]} = \frac{8}{4} = 2K=[A][B]​=48​=2

  1. Hence, the correct option is:

2\boxed{2}2​

So, option B is correct.

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