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Chemical Bonding and Molecular Structure question

2023 · 15 Apr · Shift 1 · Q10

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Chemical Bonding and Molecular Structure
2023 · 15 Apr · Shift 1 · Q10

Chemical Bonding and Molecular Structure question

2023 · 15 Apr · Shift 1 · Q10

JEE MainChemistryChemical Bonding and Molecular StructureMCQ+4 / −1

Consider the following statements: (A)

NF_3

molecule has a trigonal planar structure. (B) Bond length of

\mathrm{N}_{2}

is shorter than

\mathrm{O}_{2}

. (C) Isoelectronic molecules or ions have identical bond order. (D) Dipole moment of

\mathrm{H}_{2}\mathrm{S}

is higher than that of water molecule. Choose the correct answer from the options given below:

A
(C) and (D) are correct
B
(A) and (B) are correct
C
(B) and (C) are correct
D
(A) and (D) are correct

View written solutionFree

Correct answer: C

Check statement (A): $NF_3$ molecule has a trigonal planar structure

Nitrogen in $NF_3$ has 5 valence electrons.
- It forms 3 bonds with 3 fluorine atoms.
- One lone pair remains on nitrogen.
So, the electron pair geometry is tetrahedral, and the molecular shape is trigonal pyramidal, not trigonal planar.

Hence, (A) is false.
Check statement (B): Bond length of $N_2$ is shorter than $O_2$

Using molecular orbital theory:
- For $N_2$ , bond order $= 3$
- For $O_2$ , bond order $= 2$
Greater bond order implies stronger and shorter bond.

Therefore,
$\text{Bond length of } N_2 < \text{Bond length of } O_2$
Hence, (B) is true.
Check statement (C): Isoelectronic molecules or ions have identical bond order

Isoelectronic species have the same total number of electrons, and for diatomic species with similar MO filling pattern, they have the same bond order.

For example:
- $N_2$ has 14 electrons, bond order $= 3$
- $CO$ has 14 electrons, bond order $= 3$
- $CN^-$ has 14 electrons, bond order $= 3$
Thus, this statement is taken as true in standard JEE context.

Hence, (C) is true.
Check statement (D): Dipole moment of $H_2S$ is higher than that of water molecule

Known dipole moments:
- $\mu(H_2O) \approx 1.85\,D$
- $\mu(H_2S) \approx 0.95\,D$
Therefore,
$\mu(H_2S) < \mu(H_2O)$
Hence, (D) is false.
Final evaluation of options
- (A) false
- (B) true
- (C) true
- (D) false
So the correct statements are (B) and (C).

Therefore, the correct option is C.

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