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Biomolecules question

2025 · 2 Apr · Shift 2 · Q4
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Biomolecules question

2025 · 2 Apr · Shift 2 · Q4

JEE MainChemistryBiomoleculesMCQ+4 / −1
A tetrapeptide, " xxx " on complete hydrolysis produced glycine (Gly), alanine (Ala), valine (Val), leucine (Leu) in equimolar proportion each. The number of tetrapeptides (sequences) possible involving each of these amino acids is :
  1. A
    32
  2. B
    24
  3. C
    8
  4. D
    16
View written solutionFree

Correct answer: B

  1. Interpret the question

A tetrapeptide on complete hydrolysis gives:

  • Gly
  • Ala
  • Val
  • Leu

in equimolar proportion each.

This means the tetrapeptide contains one molecule each of these four different amino acids.

So the problem reduces to:

How many distinct sequences can be formed using 4 different amino acids, each used exactly once?


  1. Count the number of possible sequences

For a peptide, changing the order of amino acids gives a different peptide because the N-terminal to C-terminal order matters.

Thus, the number of different tetrapeptides is the number of permutations of 4 distinct amino acids:

4!=4×3×2×1=244! = 4 \times 3 \times 2 \times 1 = 244!=4×3×2×1=24


  1. Check options
  • A: 323232 ❌
  • B: 242424 ✅
  • C: 888 ❌
  • D: 161616 ❌

  1. Final answer

The number of tetrapeptides possible is:

24\boxed{24}24​

So the correct option is B.

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