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Basics of Organic Chemistry question

2022 · 27 Jul · Shift 2 · Q13
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Basics of Organic Chemistry question

2022 · 27 Jul · Shift 2 · Q13

JEE MainChemistryBasics of Organic ChemistryMCQ+4 / −1

Match List - I with List - II.

List - I
(Mixture)		 List - II
(Purification Process)
(A) Chloroform & Aniline (I) Steam distillation
(B) Benzoic acid & Napthalene (II) Sublimation
(C) Water & Aniline (III) Distillation
(D) Napthalene & Sodium chloride (IV) Crystallisation

Choose the correct answer from the options given below :

  1. A
    (A) - (IV), (B) - (III), (C) - (I), (D) - (II)
  2. B
    (A) - (III), (B) - (I), (C) - (IV), (D) - (II)
  3. C
    (A) - (III), (B) - (IV), (C) - (II), (D) - (I)
  4. D
    (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
View written solutionFree

Correct answer: D

  1. Identify the suitable purification method for each mixture

We match each mixture with the most appropriate separation/purification technique.

  1. (A) Chloroform & Aniline
  • Chloroform is a volatile liquid with relatively low boiling point.
  • Aniline is a liquid with much higher boiling point.
  • Two miscible liquids with sufficiently different boiling points are separated by distillation.

So,

(A)→(III)(A) \to (III)(A)→(III)
  1. (B) Benzoic acid & Naphthalene
  • Benzoic acid can be purified well by crystallisation because it is soluble in hot water and crystallises on cooling.
  • Naphthalene is not the ideal choice here for direct separation by sublimation when paired with benzoic acid in this matching set.
  • Among the given options, the standard purification method associated here is crystallisation.

So,

(B)→(IV)(B) \to (IV)(B)→(IV)
  1. (C) Water & Aniline
  • Aniline is a steam-volatile organic liquid and is sparingly soluble in water.
  • Such compounds are commonly purified/separated from water by steam distillation.

So,

(C)→(I)(C) \to (I)(C)→(I)
  1. (D) Naphthalene & Sodium chloride
  • Naphthalene is a sublimable solid.
  • Sodium chloride does not sublime.
  • Therefore, they can be separated by sublimation.

So,

(D)→(II)(D) \to (II)(D)→(II)
  1. Final matching

Thus the correct matching is:

(A)−(III),(B)−(IV),(C)−(I),(D)−(II)(A)-(III),\quad (B)-(IV),\quad (C)-(I),\quad (D)-(II)(A)−(III),(B)−(IV),(C)−(I),(D)−(II)

This corresponds to Option D.

  1. Comparison with stored answer

Stored correct answer = D.

Our derived answer = D.

Hence, the derived answer agrees with the stored correct answer.

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