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Basics of Organic Chemistry question

2021 · 20 Jul · Shift 2 · Q1
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Basics of Organic Chemistry question

2021 · 20 Jul · Shift 2 · Q1

JEE MainChemistryBasics of Organic ChemistryMCQ+4 / −1
Which one of the following pairs of isomers is an example of metamerism?
  1. A
    JEE Main 2021 (Online) 20th July Evening Shift Chemistry - Basics of Organic Chemistry Question 164 English Option 1
  2. B
    JEE Main 2021 (Online) 20th July Evening Shift Chemistry - Basics of Organic Chemistry Question 164 English Option 2
  3. C
    JEE Main 2021 (Online) 20th July Evening Shift Chemistry - Basics of Organic Chemistry Question 164 English Option 3
  4. D
    JEE Main 2021 (Online) 20th July Evening Shift Chemistry - Basics of Organic Chemistry Question 164 English Option 4
View written solutionFree

Correct answer: D

  1. Identify what is being asked

We need to find which pair of isomers shows metamerism.

  1. Recall the definition of metamerism

Metamerism is a type of structural isomerism shown by compounds having:

  • the same molecular formula,
  • the same functional group, but
  • different alkyl groups on the two sides of a polyvalent atom or functional group such as −O−-O-−O−, −S−-S-−S−, −NH−-NH-−NH−, etc.

Typical examples:

  • Ethers: R−O−R′R-O-R'R−O−R′
  • Secondary amines: R−NH−R′R-NH-R'R−NH−R′
  • Thioethers: R−S−R′R-S-R'R−S−R′

Example of metamers:

CH3−O−C3H7andC2H5−O−C2H5CH_3-O-C_3H_7 \quad \text{and} \quad C_2H_5-O-C_2H_5CH3​−O−C3​H7​andC2​H5​−O−C2​H5​

Both are ethers with molecular formula C4H10OC_4H_{10}OC4​H10​O, but the alkyl groups attached to oxygen are distributed differently.

  1. Issue with the provided question

The options corresponding to A, B, C, and D are not visible in the prompt. So the actual pairs cannot be evaluated one by one.

  1. Use the stored correct answer

The stored correct answer is D. Since metamerism corresponds to a pair where the same functional group has different alkyl groups on either side of a polyvalent atom, option D must be the pair satisfying this condition.

  1. Conclusion

Therefore, the correct option is:

D\boxed{D}D​
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