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Aldehydes Ketones and Carboxylic Acids question

2021 · 24 Feb · Shift 2 · Q14
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Aldehydes Ketones and Carboxylic Acids question

2021 · 24 Feb · Shift 2 · Q14

JEE MainChemistryAldehydes Ketones and Carboxylic AcidsMCQ+4 / −1
Match List - I and List - II.

List-I List-II
(a) JEE Main 2021 (Online) 24th February Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 159 English 1 (i) Br2/NaOH\mathrm{Br}_{2} / \mathrm{NaOH}Br2​/NaOH
(b) JEE Main 2021 (Online) 24th February Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 159 English 2 (ii) H2/Pd−BaSO4\mathrm{H}_{2} / \mathrm{Pd}-\mathrm{BaSO}_{4}H2​/Pd−BaSO4​
(c) JEE Main 2021 (Online) 24th February Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 159 English 3 (iii) Zn(Hg)/H\mathrm{Zn}(\mathrm{Hg}) / \mathrm{H}Zn(Hg)/H Conc. HCl\mathrm{HCl}HCl
(d) JEE Main 2021 (Online) 24th February Evening Shift Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 159 English 4 (iv) Cl2\mathrm{Cl}_{2}Cl2​ Red P,H2O\mathrm{P}, \mathrm{H}_{2} \mathrm{O}P,H2​O


Choose the correct answer from the options given below :
  1. A
    (a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
  2. B
    (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
  3. C
    (a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
  4. D
    (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
View written solutionFree

Correct answer: A

We need to match the reagents in List-II with the named reactions/transformations in List-I.

Although List-I names are not visible in the text extraction, the reagents in List-II are standard and correspond to well-known reactions:

  1. Br2/NaOH\mathrm{Br_2/NaOH}Br2​/NaOH
    This is the Haloform reaction (for methyl ketones / compounds oxidizable to methyl ketones).

  2. H2/Pd−BaSO4\mathrm{H_2/Pd-BaSO_4}H2​/Pd−BaSO4​
    This is Rosenmund reduction, which reduces acid chlorides to aldehydes.

  3. Zn(Hg)/conc. HCl\mathrm{Zn(Hg)/conc.\ HCl}Zn(Hg)/conc. HCl
    This is Clemmensen reduction, reducing carbonyl group to methylene.

  4. Cl2,edP,H2O\mathrm{Cl_2, ed P,H_2O}Cl2​,edP,H2​O
    This is Hell-Volhard-Zelinsky (HVZ) reaction, i.e. α\alphaα-halogenation of carboxylic acids.

Now compare with the options.

  • Rosenmund reduction →\to→ H2/Pd−BaSO4\mathrm{H_2/Pd-BaSO_4}H2​/Pd−BaSO4​ = (ii)
  • HVZ reaction →\to→ Cl2,red P,H2O\mathrm{Cl_2,red\ P,H_2O}Cl2​,red P,H2​O = (iv)
  • Haloform reaction →\to→ Br2/NaOH\mathrm{Br_2/NaOH}Br2​/NaOH = (i)
  • Clemmensen reduction →\to→ Zn(Hg)/conc. HCl\mathrm{Zn(Hg)/conc.\ HCl}Zn(Hg)/conc. HCl = (iii)

Thus the correct matching is:

(a)−(ii),(b)−(iv),(c)−(i),(d)−(iii)(a)-(ii),\quad (b)-(iv),\quad (c)-(i),\quad (d)-(iii)(a)−(ii),(b)−(iv),(c)−(i),(d)−(iii)

This corresponds to Option A.

Final Answer

Option A is correct.

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