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Aldehydes Ketones and Carboxylic Acids question

2009 · Shift 0 · Q9
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Aldehydes Ketones and Carboxylic Acids question

2009 · Shift 0 · Q9

JEE MainChemistryAldehydes Ketones and Carboxylic AcidsMCQ+4 / −1
In Cannizzaro reaction given below 2PhCHO→ (−)OH PhCH2OH+PhCOO−2\text{PhCHO} \xrightarrow{\,^{(-)}\text{OH}\,} \text{PhCH}_2\text{OH} + \text{PhCOO}^{-}2PhCHO(−)OH​PhCH2​OH+PhCOO− the slowest step is :
  1. A
    the transfer of hydride to the carbonyl group
  2. B
    the abstraction of proton from the carboxylic group
  3. C
    the attack of :OH(−):\mathop {OH}\limits^{( - )}:OH(−) at the carboxyl group
  4. D
    the deprotonation of Ph CH2OHCH_2OHCH2​OH
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