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Alcohols Phenols and Ethers question

2023 · 13 Apr · Shift 1 · Q8
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Alcohols Phenols and Ethers question

2023 · 13 Apr · Shift 1 · Q8

JEE MainChemistryAlcohols Phenols and EthersMCQ+4 / −1
2-Methyl propyl bromide reacts with C2H5O−\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}C2​H5​O− and gives 'A' whereas on reaction with C2H5OH\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}C2​H5​OH it gives 'B'. The mechanism followed in these reactions and the products 'A' and 'B' respectively are :
  1. A
    SN1,A=\mathrm{S}_{N} 1, A=SN​1,A= tert-butyl ethyl ether; SN2,B=\mathrm{S}_{N} 2, B=SN​2,B= iso-butyl ethyl ether
  2. B
    SN1, A=\mathrm{S}_{\mathrm{N}} 1, \mathrm{~A}=SN​1, A= tert-butyl ethyl ether; SN1, B=\mathrm{S}_{\mathrm{N}} 1, \mathrm{~B}=SN​1, B= 2-butyl ethyl ether
  3. C
    SN2, A=\mathrm{S}_{\mathrm{N}} 2, \mathrm{~A}=SN​2, A= iso-butyl ethyl ether; SN1, B=\mathrm{S}_{\mathrm{N}} 1, \mathrm{~B}=SN​1, B= tert-butyl ethyl ether
  4. D
    SN2, A=\mathrm{S}_{\mathrm{N}} 2, \mathrm{~A}=SN​2, A= 2-butyl ethyl ether; SN2, B=\mathrm{S}_{\mathrm{N}} 2, \mathrm{~B}=SN​2, B= iso-butyl ethyl ether
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