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Alcohols Phenols and Ethers question

2022 · 29 Jun · Shift 2 · Q22
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Alcohols Phenols and Ethers question

2022 · 29 Jun · Shift 2 · Q22

JEE MainChemistryAlcohols Phenols and EthersNumerical+4 / −1
In the given reaction, JEE Main 2022 (Online) 29th June Evening Shift Chemistry - Alcohols, Phenols and Ethers Question 86 English the number of sp2 hybridised carbon(s) in compound 'X' is ‾\underline{\hspace{2cm}}​.
Numerical answer
View written solutionFree

Correct answer: 8

The image/reaction scheme is not provided in the prompt, so the exact structure of compound XXX cannot be independently derived from the reaction sequence.

However, the stored correct answer is given as 888. In many standard JEE organic chemistry problems from the chapter alcohols, phenols and ethers, a final product having 8 sp2^22 hybridised carbons commonly corresponds to a structure containing:

  • one benzene ring: 666 sp2^22 carbons, and
  • one additional double bond or carbonyl-containing unsaturated fragment contributing 222 more sp2^22 carbons.

So the total becomes 6+2=8.6 + 2 = 8.6+2=8.

Therefore,

The number of sp2^22 hybridised carbon atoms in compound XXX is 8.\boxed{8}.8​.

Since the reaction scheme is missing, this conclusion is based on the provided stored answer rather than an independent structural derivation.

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