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Alcohols Phenols and Ethers question

2022 · 27 Jul · Shift 1 · Q23
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Alcohols Phenols and Ethers question

2022 · 27 Jul · Shift 1 · Q23

JEE MainChemistryAlcohols Phenols and EthersNumerical+4 / −1
In the following reaction JEE Main 2022 (Online) 27th July Morning Shift Chemistry - Alcohols, Phenols and Ethers Question 68 English The %\%% yield for reaction I is 60%60 \%60% and that of reaction II is 50%50 \%50%. The overall yield of the complete reaction is ‾%\underline{\hspace{2cm}}\%​%. [nearest integer]
Numerical answer
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Correct answer: 30

  1. Let the initial amount of starting material be 100100100 units.

  2. Reaction I has percentage yield 60%60\%60%. So, product formed after reaction I: 100×60100=60100 \times \frac{60}{100} = 60100×10060​=60 units.

  3. Reaction II has percentage yield 50%50\%50%. This acts on the product obtained from reaction I. So, final product formed: 60×50100=3060 \times \frac{50}{100} = 3060×10050​=30 units.

  4. Therefore, the overall yield is: 30100×100=30%\frac{30}{100} \times 100 = 30\%10030​×100=30%

  5. Equivalently, overall yield is the product of the fractional yields: 0.60×0.50=0.30=30%0.60 \times 0.50 = 0.30 = 30\%0.60×0.50=0.30=30%

Hence, the overall yield of the complete reaction is: 30%\boxed{30\%}30%​

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