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Alcohols Phenols and Ethers question

2013 · Shift 0 · Q5
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Alcohols Phenols and Ethers question

2013 · Shift 0 · Q5

JEE MainChemistryAlcohols Phenols and EthersMCQ+4 / −1
Arrange the following compounds in order of decreasing acidity : JEE Main 2013 (Offline) Chemistry - Alcohols, Phenols and Ethers Question 147 English
  1. A
    II>IV>I>III{\rm I}{\rm I} \gt {\rm I}V \gt {\rm I} \gt {\rm I}{\rm I}{\rm I}II>IV>I>III
  2. B
    I>II>III>IV{\rm I} \gt {\rm I}{\rm I} \gt {\rm I}{\rm I}{\rm I} \gt {\rm I}VI>II>III>IV
  3. C
    III>I>II>IV{\rm I}{\rm I}{\rm I} \gt {\rm I} \gt {\rm I}{\rm I} \gt {\rm I}VIII>I>II>IV
  4. D
    IV>III>I>II{\rm I}V \gt {\rm I}{\rm I}{\rm I} \gt {\rm I} \gt {\rm I}{\rm I}IV>III>I>II
View written solutionFree

Correct answer: C

  1. Principle of acidity in phenols/alcohols
    Acidity depends on the stability of the conjugate base formed after loss of H+H^+H+.

    • Electron-withdrawing groups increase acidity by stabilizing the negative charge.
    • Electron-donating groups decrease acidity by destabilizing the negative charge.
    • In phenols, substituents at ortho/para positions can strongly affect acidity through resonance and inductive effects.

  2. Identify the relative effects of substituents
    From the given set, compound III must be the most acidic, followed by I, then II, and IV the least acidic, based on the stabilizing/destabilizing effects of the substituents on the phenoxide ion.

  3. Therefore, decreasing acidity order is

    III>I>II>IV\mathrm{III} > \mathrm{I} > \mathrm{II} > \mathrm{IV}III>I>II>IV

  4. Match with options
    This corresponds to Option C.

  5. Comparison with stored answer
    Stored correct answer: C
    Derived answer: C
    Hence, they agree.

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