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Alcohols Phenols and Ethers question

2006 · Shift 0 · Q12
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Alcohols Phenols and Ethers question

2006 · Shift 0 · Q12

JEE MainChemistryAlcohols Phenols and EthersMCQ+4 / −1
Phenyl magnesium bromide reacts with methanol to give
  1. A
    a mixture of anisole and Mg(OH)Br
  2. B
    a mixture of benzene and Mg(OMe)Br
  3. C
    a mixture of toluene and Mg(OH)Br
  4. D
    a mixture of phenol and Mg(Me)Br
View written solutionFree

Correct answer: B

  1. Identify the reagent

    Phenyl magnesium bromide is a Grignard reagent: C6H5MgBr\mathrm{C_6H_5MgBr}C6​H5​MgBr

    Grignard reagents behave like strong bases as well as nucleophiles.

  2. Reaction with methanol

    Methanol is a protic compound: CH3OH\mathrm{CH_3OH}CH3​OH

    Since Grignard reagents are very strong bases, they abstract the acidic proton from alcohols.

    So the reaction is: C6H5MgBr+CH3OH→C6H6+CH3OMgBr\mathrm{C_6H_5MgBr + CH_3OH \rightarrow C_6H_6 + CH_3OMgBr}C6​H5​MgBr+CH3​OH→C6​H6​+CH3​OMgBr

    That is, PhMgBr+MeOH→PhH+Mg(OMe)Br\mathrm{PhMgBr + MeOH \rightarrow PhH + Mg(OMe)Br}PhMgBr+MeOH→PhH+Mg(OMe)Br

  3. Products formed

    • C6H6\mathrm{C_6H_6}C6​H6​ = benzene
    • Mg(OMe)Br\mathrm{Mg(OMe)Br}Mg(OMe)Br = magnesium methoxide bromide
  4. Check options

    • A: anisole + Mg(OH)Br\mathrm{Mg(OH)Br}Mg(OH)Br ❌
      • No ether formation occurs here.
    • B: benzene + Mg(OMe)Br\mathrm{Mg(OMe)Br}Mg(OMe)Br ✅
    • C: toluene + Mg(OH)Br\mathrm{Mg(OH)Br}Mg(OH)Br ❌
      • Toluene is not formed.
    • D: phenol + Mg(Me)Br\mathrm{Mg(Me)Br}Mg(Me)Br ❌
      • This is not the behavior of Grignard reagent with methanol.
  5. Final answer

    The correct product is: benzene and Mg(OMe)Br\boxed{\text{benzene and } \mathrm{Mg(OMe)Br}}benzene and Mg(OMe)Br​

    So the correct option is B.

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