Which of the following is(are) true of the intensity pattern on the screen?- ASemi circular bright and dark bands centered at point O
- BThe region very close to the point O will be dark
- CStraight bright and dark bands parallel to the X-axis.
- DHyperbolic bright and dark bands with foci symmetrically placed about O in the x-direction
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Correct answer: D
1. Geometry of the setup
Let the two coherent point sources be at in the -plane.
The screen is parallel to the -plane, so its equation is with .
A general point on the screen is
The origin is the point where the line joining meets the screen, so
2. Distances from the two sources to a point on screen
The distances are
Hence the path difference is
3. Nature of loci of constant path difference
For maxima/minima, the path difference must be constant:
- Bright:
- Dark:
Now, since this is precisely the definition of a hyperbola in the - plane of the screen, with foci at the projections of and onto the screen.
Because the sources are symmetric about , the foci are symmetrically placed about in the -direction.
So the fringe pattern consists of hyperbolic bright and dark bands.
Thus, Option D is correct.
4. Approximation near the central region
Since , we may use the far-field approximation: which simplifies to
\qquad R=\sqrt{D^2+x^2+z^2}.$$ Very close to $O$, $x,z\ll D$, so $$R\approx D$$ therefore $$\Delta\approx \frac{xd}{D}.$$ So near the center, constant $\Delta$ means $$x=\text{constant},$$ which are straight lines parallel to the $z$-axis (not the $x$-axis). Hence **Option C is false**. --- ## 5. Intensity at the point $O$ At $O=(0,D,0)$, $$r_1=r_2=\sqrt{D^2+\left(\frac d2\right)^2}$$ so $$\Delta=0.$$ Therefore the point $O$ is a **bright point**, not dark. Hence **Option B is false**. --- ## 6. Are the fringes semicircular? Semicircular fringes would mean curves centered at $O$ depending only on distance from $O$, i.e. only on $x^2+z^2$. But here the path difference depends asymmetrically on $x$ through $$r_1-r_2=\sqrt{\left(x+\frac d2\right)^2+D^2+z^2}-\sqrt{\left(x-\frac d2\right)^2+D^2+z^2},$$ so the loci are not circles centered at $O$. Thus **Option A is false**. --- ## 7. Final evaluation of options - **A:** False - **B:** False - **C:** False - **D:** True --- ## 8. Comparison with stored answer Stored correct answer: **A, B** My derived answer: **D** These do not match. The stored answer appears inconsistent with the interference condition $r_1-r_2=\text{constant}$ for two point sources and a screen parallel to the $XZ$-plane, which gives hyperbolic fringes and a bright point at $O$.More from Wave Optics
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