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Wave Optics question

2015 · Shift 1 · Q47

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JEE Advanced
Physics
Wave Optics
2015 · Shift 1 · Q47

Wave Optics question

2015 · Shift 1 · Q47

JEE AdvancedPhysicsWave OpticsNumerical+4 / −1

A Young's double slit interference arrangement with slits S1 and S2 is immersed in water (refractive index = 4/3) as shown in the figure. The positions of maxima on the surface of water are given by x2 = p2m2

\lambda

2

-

d2, where

\lambda

is the wavelength of light in air (refractive index = 1). 2d is the separation between the slits and m is an integer. The value of p is JEE Advanced 2015 Paper 1 Offline Physics - Wave Optics Question 15 English

JEE Advanced 2015 Paper 1 Offline Physics - Wave Optics Question 15 English

Numerical answer

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