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Rotational Motion question

2022 · Shift 1 · Q41
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  5. /2022 · Shift 1 · Q41

Rotational Motion question

2022 · Shift 1 · Q41

JEE AdvancedPhysicsRotational MotionNumerical+3 / −1
At time t=0t=0t=0, a disk of radius 1 m1 \mathrm{~m}1 m starts to roll without slipping on a horizontal plane with an angular acceleration of α=23rad s−2\alpha=\frac{2}{3} \mathrm{rad} \,\mathrm{s}^{-2}α=32​rads−2. A small stone is stuck to the disk. At t=0t=0t=0, it is at the contact point of the disk and the plane. Later, at time t=π st=\sqrt{\pi} \,st=π​s, the stone detaches itself and flies off tangentially from the disk. The maximum height (in mmm) reached by the stone measured from the plane is 12+x10\frac{1}{2}+\frac{x}{10}21​+10x​. The value of xxx is ‾\underline{\hspace{2cm}}​ , [Take g=10 m s−2g=10 \mathrm{~m} \mathrm{~s}^{-2}g=10 m s−2.]
Numerical answer
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