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Rotational Motion question

2020 · Shift 2 · Q45
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  5. /2020 · Shift 2 · Q45

Rotational Motion question

2020 · Shift 2 · Q45

JEE AdvancedPhysicsRotational MotionMultiple correct+4 / −2
A rod of mass m and length L, pivoted at one of its ends, is hanging vertically. A bullet of the same mass moving at speed v strikes the rod horizontally at a distance x from its pivoted end and gets embedded in it. The combined system now rotates with angular speed ω\omegaω about the pivot. The maximum angular speed ω\omegaω M is achieved for x = xM. Then JEE Advanced 2020 Paper 2 Offline Physics - Rotational Motion Question 42 English
  1. A
    ω=3vxL2+3x2\omega = {{3vx} \over {{L^2} + 3{x^2}}}ω=L2+3x23vx​
  2. B
    ω=12vxL2+12x2\omega = {{12vx} \over {{L^2} + 12{x^2}}}ω=L2+12x212vx​
  3. C
    xM=L3{x_M} = {L \over {\sqrt 3 }}xM​=3​L​
  4. D
    ωM=v2L3{\omega _M} = {v \over {2L}}\sqrt 3ωM​=2Lv​3​
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