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Rotational Motion question

2018 · Shift 1 · Q42
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Rotational Motion question

2018 · Shift 1 · Q42

JEE AdvancedPhysicsRotational MotionNumerical+3 / −1
A ring and disc are initially at rest, side by side, at the top of an inclined plane which makes an angle 60∘{60^ \circ }60∘ with the horizontal. They start to roll without slipping at the same instant of time along the shortest path. If the time difference between their reaching the ground is (2−3)/10  s,\left( {2 - \sqrt 3 } \right)/\sqrt {10} \,\,s,(2−3​)/10​s, then the height of the top of the inclined plane, in metres is ‾\underline{\hspace{2cm}}​ . Take g=10  ms−2.g = 10\,\,m{s^{ - 2}}.g=10ms−2.
Numerical answer
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