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Motion question

2020 · Shift 2 · Q48
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Motion question

2020 · Shift 2 · Q48

JEE AdvancedPhysicsMotionMultiple correct+4 / −2
Starting at time t = 0 from the origin with speed 1 ms-1, a particle follows a two-dimensional trajectory in the x-y plane so that its coordinates are related by the equation y=x22y = {{{x^2}} \over 2}y=2x2​. The x and y components of its acceleration are denoted by ax and ay, respectively. Then
  1. A
    ax = 1 ms-2 implies that when the particle is at the origin, ay = 1 ms-2
  2. B
    ax = 0 implies ay = 1 ms-2 at all times
  3. C
    at t = 0, the particle's velocity points in the x-direction
  4. D
    ax = 0 implies that at t = 1s, the angle between the particle's velocity and the x axis is 45 ∘^\circ∘
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