- A
- B
- C
- D
View written solutionFree
Correct answer: A
Step-by-step Derivation
-
Relate Mass, Density, and Volume: The mass
Mof the sphere is related to its densityρand volumeVby the formula: For a sphere of radiusR, the volume is . Substituting this into the mass equation, we get: -
Use the Condition of Constant Mass: The problem states that the total mass
Mof the sphere remains constant. SinceM, , and are all constants, the product must also be a constant. -
Differentiate with Respect to Time: To find the relationship between the rates of change, we differentiate the equation with respect to time
t. Using the product rule for differentiation(uv)' = u'v + uv': \frac{d}{dt} (\rho R^3) = \frac{d}{dt} (\text{constant}) $$$$ \left( \frac{d\rho}{dt} \right) R^3 + \rho \left( \frac{d(R^3)}{dt} \right) = 0 Applying the chain rule to the term: . -
Incorporate the Given Rate of Fractional Change in Density: The problem states that the rate of fractional change in density, , is a constant. Let's denote this constant by
C: From this, we can write . -
Substitute and Solve for Velocity: Substitute into the equation from Step 3: The velocity
vof a point on the surface is the rate of change of the radius, . So we have: We can divide the entire equation by (assuming andRare non-zero): Solving forv: 3v = -CR $$$$ v = -\frac{C}{3} R -
Conclusion: Since
Cis a constant, the term is also a constant. Therefore, the velocityvis directly proportional to the instantaneous radiusR. This corresponds to option A.
Evaluation of Options
- A: : Our derivation shows
v ∝ R. This is the correct option. - B: : Incorrect.
- C: : Incorrect.
- D: : Incorrect.
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