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Magnetism question

2024 · Shift 2 · Q41
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Magnetism question

2024 · Shift 2 · Q41

JEE AdvancedPhysicsMagnetismMultiple correct+4 / −2
A positive, singly ionized atom of mass number AMA_{\mathrm{M}}AM​ is accelerated from rest by the voltage 192 V192 \mathrm{~V}192 V. Thereafter, it enters a rectangular region of width www with magnetic field B⃗0=0.1k^\vec{B}_0=0.1 \hat{k}B0​=0.1k^ Tesla, as shown in the figure. The ion finally hits a detector at the distance xxx below its starting trajectory. [Given: Mass of neutron/proton =(5/3)×10−27 kg=(5 / 3) \times 10^{-27} \mathrm{~kg}=(5/3)×10−27 kg, charge of the electron =1.6×10−19C=1.6 \times 10^{-19} \mathrm{C}=1.6×10−19C.] JEE Advanced 2024 Paper 2 Online Physics - Magnetism Question 2 English Which of the following option(s) is(are) correct?
  1. A
    The value of xxx for H+H^{+}H+ ion is 4 cm4 \mathrm{~cm}4 cm.
  2. B
    The value of xxx for an ion with AM=144A_{\mathrm{M}}=144AM​=144 is 48 cm48 \mathrm{~cm}48 cm.
  3. C
    For detecting ions with 1≤AM≤1961 \leq A_{\mathrm{M}} \leq 1961≤AM​≤196, the minimum height (x1−x0)\left(x_1-x_0\right)(x1​−x0​) of the detector is 55 cm55 \mathrm{~cm}55 cm.
  4. D
    The minimum width www of the region of the magnetic field for detecting ions with AM=196A_{\mathrm{M}}=196AM​=196 is 56 cm56 \mathrm{~cm}56 cm.
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