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Magnetism question

2021 · Shift 2 · Q51
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  5. /2021 · Shift 2 · Q51

Magnetism question

2021 · Shift 2 · Q51

JEE AdvancedPhysicsMagnetismMCQ+3 / −1
A special metal S conducts electricity without any resistance. A closed wire loop, made of S, does not allow any change in flux through itself by inducing a suitable current to generate a compensating flux. The induced current in the loop cannot decay due to its zero resistance. This current gives rise to a magnetic moment which in turn repels the source of magnetic field or flux. Consider such a loop, of radius a, with its center at the origin. A magnetic dipole of moment m is brought along the axis of this loop from infinity to a point at distance r (>> a) from the center of the loop with its north pole always facing the loop, as shown in the figure below. The magnitude of magnetic field of a dipole m, at a point on its axis at distance r, is μ02πmr3{{{\mu _0}} \over {2\pi }}{m \over {{r^3}}}2πμ0​​r3m​, where μ\muμ 0 is the permeability of free space. The magnitude of the force between two magnetic dipoles with moments, m1 and m2, separated by a distance r on the common axis, with their north poles facing each other, is km1m2r4{{k{m_1}{m_2}} \over {{r^4}}}r4km1​m2​​, where k is a constant of appropriate dimensions. The direction of this force is along the line joining the two dipoles. JEE Advanced 2021 Paper 2 Online Physics - Magnetism Question 32 English ComprehensionWhen the dipole m is placed at a distance r from the center of the loop (as shown in the figure), the current induced in the loop will be proportional to
  1. A
    m/r3
  2. B
    m2/r2
  3. C
    m/r2
  4. D
    m2/r
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