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Laws of Motion question

2014 · Shift 1 · Q53
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  5. /2014 · Shift 1 · Q53

Laws of Motion question

2014 · Shift 1 · Q53

JEE AdvancedPhysicsLaws of MotionMultiple correct+3 / −1
In the figure, a ladder of mass m is shown leaning against a wall. It is in static equilibrium making an angle θ\thetaθ with the horizontal floor. The coefficient of friction between the wall and the ladder is μ\muμ 1 and that between the floor and the ladder is μ\muμ 2. The normal reaction of the wall on the ladder is N1 and that of the floor is N2. If the ladder is about to slip, then JEE Advanced 2014 Paper 1 Offline Physics - Laws of Motion Question 11 English
  1. A
    μ\muμ 1 = 0, μ\muμ 2 eee 0 and N2tan⁡θ=mg2{N_2}\tan \theta = {{mg} \over 2}N2​tanθ=2mg​
  2. B
    μ\muμ 1 eee 0, μ\muμ 2 = 0 and N1tan⁡θ=mg2{N_1}\tan \theta = {{mg} \over 2}N1​tanθ=2mg​
  3. C
    μ\muμ 1 eee 0, μ\muμ 2 eee 0 and N2=mg1+μ1μ2{N_2} = {{mg} \over {1 + {\mu _1}{\mu _2}}}N2​=1+μ1​μ2​mg​
  4. D
    μ\muμ 1 = 0, μ\muμ 2 eee 0 and N1tan⁡θ=mg2{N_1}\tan \theta = {{mg} \over 2}N1​tanθ=2mg​
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