- A1 : 4
- B1 : 2
- C6 : 9
- D8 : 9
View written solutionFree
Correct answer: D
Step-by-step Solution
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Recall the Ideal Gas Law: The ideal gas equation is given by , where is the pressure, is the volume, is the number of moles, is the universal gas constant, and is the absolute temperature.
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Express the Ideal Gas Law in terms of density: The number of moles can be written as the ratio of the total mass of the gas to its molar mass : . Substituting this into the ideal gas equation gives: Density, , is defined as mass per unit volume, . We can rearrange the equation to solve for density: So, the density of an ideal gas is given by:
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Set up the ratio of densities for the two gases: Let the two gases be Gas 1 and Gas 2. Their properties will be denoted by subscripts 1 and 2, respectively. The density of Gas 1 is . The density of Gas 2 is . Note that both gases are in the same vessel at a constant temperature, so the volume , temperature , and the gas constant are the same for both.
The ratio of their densities is: This can be rewritten as:
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Substitute the given values into the ratio equation: From the problem statement, we have:
- The ratio of partial pressures:
- The ratio of atomic masses (and thus molar masses for monoatomic gases):
Substituting these values into the density ratio equation:
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Calculate the final ratio of densities: So, the ratio of the densities of the two gases is 8 : 9.
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Compare with the given options: The calculated ratio 8 : 9 matches option D.
A: 1 : 4 B: 1 : 2 C: 6 : 9 (which simplifies to 2 : 3) D: 8 : 9
The correct option is D.
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