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Electrostatics question

2011 · Shift 1 · Q67
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Electrostatics question

2011 · Shift 1 · Q67

JEE AdvancedPhysicsElectrostaticsNumerical+3 / −1
Four point charges, each of +q, are rigidly fixed at the four corners of a square planar soap film of side a. The surface tension of the soap film is γ\gammaγ. The system of charges and planar film are in equilibrium, and a=k[q2γ]1/Na = k{\left[ {{{{q^2}} \over \gamma }} \right]^{1/N}}a=k[γq2​]1/N, where k is a constant. Then N is ‾\underline{\hspace{2cm}}​.
Numerical answer
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