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Electrostatics question

2010 · Shift 2 · Q45
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Electrostatics question

2010 · Shift 2 · Q45

JEE AdvancedPhysicsElectrostaticsMCQ+2 / −0.5
A tiny spherical oil drop carrying a net charge qqq is balanced in still air with a vertical uniform electric field of strength 81π7×105  Vm−1.{{81\pi } \over 7} \times {10^5}\,\,V{m^{ - 1}}.781π​×105Vm−1. When the field is switched off, the drop is observed to fall with terminal velocity 2×10−3  ms−1.2 \times {10^{ - 3}}\,\,m{s^{ - 1}}.2×10−3ms−1. Given g=9.8 m s−2,g = 9.8\,m\,{s^{ - 2}},g=9.8ms−2, viscosity of the air =1.8×10−5  Ns m−2= 1.8 \times {10^{ - 5}}\,\,Ns\,{m^{ - 2}}=1.8×10−5Nsm−2 and the density of coil =900kgm−3,=900kg{m^{ - 3}},=900kgm−3, the magnitude of qqq is
  1. A
    1.6×10−19C1.6 \times {10^{ - 19}}C1.6×10−19C
  2. B
    3.2×10−19C3.2 \times {10^{ - 19}}C3.2×10−19C
  3. C
    4.8×10−19C4.8 \times {10^{ - 19}}C4.8×10−19C
  4. D
    8.0×10−19C8.0 \times {10^{ - 19}}C8.0×10−19C
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