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Atoms and Nuclei question

2016 · Shift 2 · Q43
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  5. /2016 · Shift 2 · Q43

Atoms and Nuclei question

2016 · Shift 2 · Q43

JEE AdvancedPhysicsAtoms and NucleiMCQ+3 / −1
An accident in a nuclear laboratory resulted in deposition of a certain amount of radioactive material of half-life 18 days inside the laboratory. Tests revealed that the radiation was 64 times more than the permissible level required for safe operation of the laboratory. What is the minimum number of days after which the laboratory can be considered safe for use?
  1. A
    64
  2. B
    90
  3. C
    108
  4. D
    120
View written solutionFree

Correct answer: C

  1. Let the initial radiation level be R0R_0R0​.

    The laboratory is safe when radiation falls to the permissible level RpR_pRp​.

    Given: R0=64RpR_0 = 64R_pR0​=64Rp​

  2. Radioactive decay follows: R=R0(12)t/T1/2R = R_0\left(\frac{1}{2}\right)^{t/T_{1/2}}R=R0​(21​)t/T1/2​ where half-life T1/2=18T_{1/2} = 18T1/2​=18 days.

  3. For the laboratory to become safe: R=RpR = R_pR=Rp​

    So, Rp=64Rp(12)t/18R_p = 64R_p\left(\frac{1}{2}\right)^{t/18}Rp​=64Rp​(21​)t/18

  4. Cancel RpR_pRp​ from both sides: 1=64(12)t/181 = 64\left(\frac{1}{2}\right)^{t/18}1=64(21​)t/18

    Since 64=2664 = 2^664=26, 1=26⋅2−t/181 = 2^6 \cdot 2^{-t/18}1=26⋅2−t/18 26−t/18=12^{6 - t/18} = 126−t/18=1

  5. Therefore, 6−t18=06 - \frac{t}{18} = 06−18t​=0 t18=6\frac{t}{18} = 618t​=6 t=108 dayst = 108\text{ days}t=108 days

  6. So the minimum time required is: 108 days\boxed{108\text{ days}}108 days​

  7. Checking options:

    • A: 646464 days →\rightarrow→ incorrect
    • B: 909090 days →\rightarrow→ incorrect
    • C: 108108108 days →\rightarrow→ correct
    • D: 120120120 days →\rightarrow→ incorrect

Therefore, the correct answer is Option C.

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