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Probability question

2025 · Shift 1 · Q18
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  5. /2025 · Shift 1 · Q18

Probability question

2025 · Shift 1 · Q18

JEE AdvancedMathematicsProbabilityMCQ+3 / −1
Three students S1,S2,S_1, S_2,S1​,S2​, and S3S_3S3​ are given a problem to solve. Consider the following events: U: At least one of S1,S2,S_1, S_2,S1​,S2​, and S3S_3S3​ can solve the problem, V: S1S_1S1​ can solve the problem, given that neither S2S_2S2​ nor S3S_3S3​ can solve the problem, W: S2S_2S2​ can solve the problem and S3S_3S3​ cannot solve the problem, T: S3S_3S3​ can solve the problem. For any event EEE, let P(E)P(E)P(E) denote the probability of EEE. If P(U)=12P(U) = \dfrac{1}{2}P(U)=21​, P(V)=110P(V) = \dfrac{1}{10}P(V)=101​, and P(W)=112P(W) = \dfrac{1}{12}P(W)=121​, then P(T)P(T)P(T) is equal to
  1. A
    1336\dfrac{13}{36}3613​
  2. B
    13\dfrac{1}{3}31​
  3. C
    1960\dfrac{19}{60}6019​
  4. D
    14\dfrac{1}{4}41​
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