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Probability question

2011 · Shift 2 · Q29
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  5. /2011 · Shift 2 · Q29

Probability question

2011 · Shift 2 · Q29

JEE AdvancedMathematicsProbabilityMultiple correct+4 / −1
Let EEE and FFF be two independent events. The probability that exactly one of them occurs is  1125\,{{11} \over {25}}2511​ and the probability of none of them occurring is  225\,{{2} \over {25}}252​. If P(T)P(T)P(T) denotes the probability of occurrence of the event T,T,T, then
  1. A
    P(E)=45,P(F)=35P\left( E \right) = {4 \over 5},P\left( F \right) = {3 \over 5}P(E)=54​,P(F)=53​
  2. B
    P(E)=15,P(F)=25P\left( E \right) = {1 \over 5},P\left( F \right) = {2 \over 5}P(E)=51​,P(F)=52​
  3. C
    P(E)=25,P(F)=15P\left( E \right) = {2 \over 5},P\left( F \right) = {1 \over 5}P(E)=52​,P(F)=51​
  4. D
    P(E)=35,P(F)=45P\left( E \right) = {3 \over 5},P\left( F \right) = {4 \over 5}P(E)=53​,P(F)=54​
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