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Parabola question

2016 · Shift 2 · Q31
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  2. /JEE Advanced
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  5. /2016 · Shift 2 · Q31

Parabola question

2016 · Shift 2 · Q31

JEE AdvancedMathematicsParabolaMultiple correct+4 / −2
Let PPP be the point on the parabola y2=4x{y^2} = 4xy2=4x which is at the shortest distance from the center SSS of the circle x2+y2−4x−16y+64=0{x^2} + {y^2} - 4x - 16y + 64 = 0x2+y2−4x−16y+64=0. Let QQQ be the point on the circle dividing the line segment SPSPSP internally. Then
  1. A
    SP=25SP = 2\sqrt 5SP=25​
  2. B
    SQ:QP=(5+1):2SQ:QP = \left( {\sqrt 5 + 1} \right):2SQ:QP=(5​+1):2
  3. C
    the xxx-intercept of the normal to the parabola at PPP is 666
  4. D
    the slope of the tangent to the circle at QQQ is 12{1 \over 2}21​
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