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Parabola question

2015 · Shift 2 · Q31
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  5. /2015 · Shift 2 · Q31

Parabola question

2015 · Shift 2 · Q31

JEE AdvancedMathematicsParabolaNumerical+4 / −1
Suppose that the foci of the ellipse x29+y25=1{{{x^2}} \over 9} + {{{y^2}} \over 5} = 19x2​+5y2​=1 are (f1,0)\left( {{f_1},0} \right)(f1​,0) and (f2,0)\left( {{f_2},0} \right)(f2​,0) where f1>0{{f_1} \gt 0}f1​>0 and f2<0{{f_2} \lt 0}f2​<0. Let P1{P_1}P1​ and P2{P_2}P2​ be two parabolas with a common vertex at (0,0)(0,0)(0,0) and with foci at (f1,0)\left( {{f_1},0} \right)(f1​,0) and (2f2,0)\left( 2{{f_2},0} \right)(2f2​,0), respectively. Let T1{T_1}T1​ be a tangent to P1{P_1}P1​ which passes through (2f2,0)\left( 2{{f_2},0} \right)(2f2​,0) and T2{T_2}T2​ be a tangent to P2{P_2}P2​ which passes through (f1,0)\left( {{f_1},0} \right)(f1​,0). If m1{m_1}m1​ is the slope of T1{T_1}T1​ and m2{m_2}m2​ is the slope of T2{T_2}T2​, then the value of (1m12+m22)\left( {{1 \over {m_1^2}} + m_2^2} \right)(m12​1​+m22​) is
Numerical answer
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