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Limits Continuity and Differentiability question

2020 · Shift 2 · Q24

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JEE Advanced
Mathematics
Limits Continuity and Differentiability
2020 · Shift 2 · Q24

Limits Continuity and Differentiability question

2020 · Shift 2 · Q24

JEE AdvancedMathematicsLimits Continuity and DifferentiabilityNumerical+3 / −1

The value of the limit

\mathop {\lim }\limits_{x \to {\pi \over 2}} {{4\sqrt 2 (\sin 3x + \sin x)} \over {\left( {2\sin 2x\sin {{3x} \over 2} + \cos {{5x} \over 2}} \right) - \left( {\sqrt 2 + \sqrt 2 \cos 2x + \cos {{3x} \over 2}} \right)}}

is ...........

Numerical answer

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