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Limits Continuity and Differentiability question

2008 · Shift 1 · Q32
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  2. /JEE Advanced
  3. /Mathematics
  4. /Limits Continuity and Differentiability
  5. /2008 · Shift 1 · Q32

Limits Continuity and Differentiability question

2008 · Shift 1 · Q32

JEE AdvancedMathematicsLimits Continuity and DifferentiabilityMultiple correct+4 / −2
Let f(x)f(x)f(x) be a non-constant twice differentiable function defined on (−∞,∞)\left( { - \infty ,\infty } \right)(−∞,∞) such that f(x)=f(1−x)f\left( x \right) = f\left( {1 - x} \right)f(x)=f(1−x) and f′(14)=0.f'\left( {{1 \over 4}} \right) = 0.f′(41​)=0. Then,
  1. A
    f′′(x)f''\left( x \right)f′′(x) vanishes at least twice on [0,1]\left[ {0,1} \right][0,1]
  2. B
    f′(12)=0f'\left( {{1 \over 2}} \right) = 0f′(21​)=0
  3. C
    ∫−1/21/2f(x+12)sin⁡x dx=0\int\limits_{ - 1/2}^{1/2} {f\left( {x + {1 \over 2}} \right)\sin x\,dx} = 0−1/2∫1/2​f(x+21​)sinxdx=0
  4. D
    ∫01/2f(t)esin⁡ πtdt=∫1/21f(1−t)esin⁡ πtdt\int\limits_0^{1/2} {f\left( t \right){e^{\sin \,\pi t}}dt = } \int\limits_{1/2}^1 {f\left( {1 - t} \right){e^{\sin \,\pi t}}dt}0∫1/2​f(t)esinπtdt=1/2∫1​f(1−t)esinπtdt
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